How Many Protons In Nitrogen

Question: Nitrogen (Diminutive Number vii) has stable isotopes (half-life greater than 1 sec) of mass numbers 13, 14, 15, xvi and 17.  Calculate number of protons and neutrons in each of the isotopes of nitrogen.

Solution:

The Atomic Number (Z) of Nitrogen is seven. The atomic number is e'er equal to the number of protons. And the number of protons always equals the electron number in an uncharged atom so that the cantlet is electrically neutral.

Therefore, an uncharged Nitrogen atom always has 7 protons and seven electrons.

 An isotope is formed when the neutron number varies in an cantlet of the aforementioned element. This changes the mass number in an cantlet's nucleus since the mass number A is the sum of protons and neutrons. The proton number remains unchanged.

 mass number A= Number of protons (p) + number of neutrons (n)

 The mass number is written every bit a superscript next to the chemical element's symbol as,

So, the number of neutrons in dissimilar Nitrogen isotopes ^xiii N, ¹⁴ N, ^xv Due north, ¹⁶ North, and ¹⁷ Northward is-

^xiii N Isotope:

Mass number =xiii (Given)

mass number (A) = number of protons (p) + number of neutrons (northward)

A= p+ n

Therefore, n= A-p = 13-7 = 6.

Solution using log tabular array-

n= A-p

Applying log_ten on both sides

log₁₀ n= log (A-Z)

log_ten northward= log_x (13-7) =log_ten 6=0.7782

Applying antilog,

due north =Antilog (0.7782)

6.001 = half dozen

The number of neutrons in the ¹³N Isotope is 6, and the number of protons is 7.

¹⁴ N Isotope

Mass number =14 (Given)

mass number (A) = number of protons (p) + number of neutrons (n)

A= p+ due north

Therefore, n= A-p = 14-vii = vii.

Solution using log table-

n= A-p

Applying log₁₀ on both sides

log_ten north= log (A-Z)

log₁₀ northward= log_x (xiv-7) = log_x 7 =0.8451

Applying antilog,

n =Antilog (0.8451) = vii

The number of neutrons in the ¹⁴Due north Isotope is 7, and the number of protons is 7.

¹⁵ Due north Isotope

Mass number =fifteen (Given)

mass number (A) = number of protons (p) + number of neutrons (due north)

A= p+ n

Therefore, due north= A-p = fifteen - 7 = 8.

Solution using log tabular array-

northward= A-p

Applying log_x on both sides

log₁₀ northward= log (A-Z)

log₁₀ n= log₁₀ (14-7) = log_x 8 =0.9031

Applying antilog,

n =Antilog (0.9031) = 8

The number of neutrons in the ¹⁵N Isotope is 8, and the number of protons is 7.

¹⁶ N Isotope

Mass number =16 (Given)

mass number (A) = number of protons (p) + number of neutrons (n)

A= p+ n

Therefore, due north= A-p = 16 - 7 = nine.

Solution using log table-

n= A-p

Applying log₁₀ on both sides

log_x n= log (A-Z)

log_ten n= log₁₀ (16-7) = log₁₀ 9 =0.9542

Applying antilog,

n =Antilog (0.9542) = ix

The number of neutrons in the ¹⁶N Isotope is ix, and the number of protons is 7.

¹⁷ Due north Isotope

Mass number =17 (Given)

mass number (A) = number of protons (p) + number of neutrons (n)

A= p+ n

Therefore, n= A-p = 17 - seven = 10.

Solution using log tabular array-

n= A-p

Applying log₁₀ on both sides

log_ten n= log (A-Z)

log₁₀ n= log₁₀ (17-seven) = log_x ten =1.000

Applying antilog,

n =Antilog (1.000) = ten

The number of neutrons in the ¹⁷Due north Isotope is 10, and the number of protons is vii.

How Many Protons In Nitrogen,

Source: https://www.curlyarrows.com/calculate-number-protons-and-neutrons-nitrogen-isotopes-13n-14n-15n-16n-and-17n

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